limewater titration
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AIM OF THE EXPERIMENT
The aim of the experiment is to determine the concentration of a sample of limewater as accurately as possible.
EQUIPMENT/MATERIALS
In this experiment, I will use 250cm3 of limewater which contains approximately 1g dm-3 of calcium hydroxide. I will also use hydrochloric acid which I will have to dilute, as it's current concentration (2 mol dm-3) is too strong for my titration I will calculate the dilution factor later in my plan. I will use methyl orange as an indicator as it has a relatively low end point which is around about neutral so it is good for a neutralisation experiment.
To carry out the titration, the apparatus I will need is as follows:
1 burette
1 metal stand and clamp
1 25cm3 pipette and syringe
1 mixing flask
1 conical flask
2 beakers
1 plastic funnel
1 distilled water dispenser
1 volumetric flask and stopper
1 white tile
CALCULATION TO DETERMINE THE DILUTION FACTOR OF THE HYDROCHLORIC ACID
This a balanced equation for the reaction that will take place:
lime water is calcium hydroxide (or slaked lime) dissolved in water
The type of reaction that I will use in the titration is a neutralisation reaction between the lime water and the hydrochloric acid:
alkali +acid salt+ water
Ca(OH)2(aq) + 2HCl(aq) CaCl2 + 2H2O
I am provided with 250cm3 of limewater with approximately 1g dm-3 of calcium hydroxide.
I will use approximately 25cm3 of limewater in each titration this contains approximately 0.025g of calcium hydroxide.
First, I must determine the approximate concentration of the limewater:
RMM of Ca(OH)2 = 74.1
Approx Ca(OH)2 g dm-3 =1g dm-3
1
74.1
=1...